Ok, I'll continue it if you allow me to do so.
You obtained the fractions as 16/100 and 31/100
Then in whole numbers;
If I'm not mistaken, copper (II) nitrate is slightly blue. Perhaps you won't notice it just by looking at it but if you place a blank white page behind a beaker containing copper(II) nitrate, you'll see the difference.
5. Yup you did it well. Do you know how you got there and why multiply?
Look here, you had 0.016 moles of copper reacting, k? Then, Mg act atom for atom as copper. Therefore, if one atom of copper reacted, one atom of Mg will react.
The same way round, if 0.016 mol of Cu react, 0.016 mol of Mg will react. Got it?
But Mg has a different mass compared to Cu.
0.016 mol of Cu has a mass of (0.016 x 65.4)g
0.016 mol of Mg has a mass of (0.016 x 24.3)g
Hope it helped!