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how do i prove this identity
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Nov 5, 2009, 04:27 PM
sgmartin
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Posts: 1
how do i prove this identity
sin2x/sinx - cos2x/cosx = secx
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Nov 5, 2009, 05:17 PM
#2
ebaines
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Join Date: Apr 2007
Location: Illinois, US
Posts: 3,766
Remember these important identities:
sin2x = 2sinxcosx
cos2x = cos^2x - sin^x
= 2 cos^x - 1
= 1-2sin^2x.
That second identity for cos2x looks promising, since you will be dividing by cosx. Try it, and see if you make progress.
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