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    mark_ycb's Avatar
    mark_ycb Posts: 1, Reputation: 1
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    #1

    Mar 15, 2008, 05:05 PM
    How to calculate the quantity of heat absorbed with any substance? Is it a equation?
    How to calculate the quantity of heat absorbed with any substance? Is it a equation?
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #2

    Mar 16, 2008, 02:36 AM
    What do you mean by "quantity of heat"?
    questhelper's Avatar
    questhelper Posts: 1, Reputation: 1
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    #3

    Apr 19, 2008, 01:01 PM
    It's quite simple actually. The equation you need to use is q=mcΔT

    where q = quantity of heat in Joules (J)
    m = mass of the substance in grams (g) *remember that 1 mL = 1 g
    c = specific heat capacity
    (there are many different specific heat capacities for many different substances)
    water has a SHC of 4.18 and ice has 2.01, try and find a table for other substances
    ΔT = the change in temperature (always the highest temp minus the lowest)
    (T2-T1) (ex/ 32-12 = 20)
    helpmex123's Avatar
    helpmex123 Posts: 3, Reputation: 1
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    #4

    Jan 2, 2010, 04:25 PM
    the accepted value for the energy content of a peanut is 30.2 kj per gram. The student measured 100.0 g of water into a metal can and placed the can on a ring stand. The peanut was attatched to a wire suspended under the can. The initial temp. of water was recoreded as 22.0 C. the peanut was ignited and allowed to burn. When the peanut finished burniing, the final water temp was 57.0 C. the students experimental value for the energy content of this peanut was 25.9 kj per gram.

    calculate the total amount of heat absorbed by the water in the given experiment.
    include a numerical setup and the calculated result.
    helpmex123's Avatar
    helpmex123 Posts: 3, Reputation: 1
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    #5

    Jan 2, 2010, 04:27 PM

    Helpp please
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #6

    Jan 4, 2010, 01:24 AM

    You can use the explanation given by the previous poster.

    I'll re say it, just in case:



    Q is the amount of heat energy
    m is the mass of water
    c is the specific heat capacity of water (which is 4.18 J/(kgK))
    theta is the change in temperature of the water.
    jbwaren's Avatar
    jbwaren Posts: 1, Reputation: 1
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    #7

    Mar 2, 2011, 09:06 PM


    100*4.18*29-22
    =12100
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