Originally Posted by

**khadoura4** For parts (a) and (b) find the derivative of the function and simplify your result.Then find the equation of the tangent line at the given point.

equation point

a. y=5x-2/X2+1 (1,3/2)

Is that

?

Use ^ for power, as in x^2. Please use proper grouping symbols. As written it is

. I assume you meant the former?

If so, use the quotient rule to find the derivative. Then, plug in x=1 to find the slope, m, at that point.

Then, to find the tangent line, use y=mx+b. Plug in your slope, m, just found and the x and y coordinates given. Solve for b and you're done.