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hayzemay · Oct 17, 2007, 03:56 AM

KCl (1.4720 g) was made up to 250 cm3 solution. 25 cm3 reequired 21.13 cm3 AgNO3 for titration

KCl + AgNO3 à AgCl + KNO3

What is the molarity of AgNO3

templelane · Oct 17, 2007, 04:14 AM

The question has two parts:-
Forst you need to work out the molarity of KCl
Use this equation

Amount (moles) = mass (grams) x volume (litres)

Remember to change the units of the volume form cm^3 to l

Second part knowing how many moles of KCL you can work out the moles of AgNO3
Take note that you only need a tenth of the initial soultion molarity you worked out
The equation shows the ratio of KCL:AGNO3 is 1:1

So if KCl works out ot be 10M (it's not) then you use 1M to react with 21.13 cm^3

25/21.13 = 1.18

1M /1.18 = 0.85M of AgNO3

Does that make sense?

If not I'll explain it a different way. In fact this website explains it differently but very nicely (they use less steps than me) Titration Calculations

hayzemay · Oct 17, 2007, 04:16 AM

Thanks ever so much