| Since the equation is a quatratic, you need to think about how it could be factored to yields one solution of 3. Recall that all quadratic equations have two solutions, let's call them A and B, and can be written as:
(x-A)(x-B) = 0.
In this case you are told that one of the answers is 3. You can replace the A with 3, and you have:
(x-3)(x-B) = 0.
Multiply this out, compare to the formula you were given , and you should be able to solve for B, and then k. Try it and let us know how it goes. |