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		<title>Ask Me Help Desk - Chemistry</title>
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			<title>Ask Me Help Desk - Chemistry</title>
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		<item>
			<title>which one is the limiting reagent?</title>
			<link>http://www.askmehelpdesk.com/chemistry/one-limiting-reagent-417904.html</link>
			<pubDate>Sat, 21 Nov 2009 01:04:00 GMT</pubDate>
			<description>A 10mL solution of 0.32M KOH was mixed with 25mL of 0.12M HBr solution. which one is the limiting reagent? 
 
I think HBr is limiting reagent.......... 
 
Please help me</description>
			<content:encoded><![CDATA[<div>A 10mL solution of 0.32M KOH was mixed with 25mL of 0.12M HBr solution. which one is the limiting reagent?<br />
<br />
I think HBr is limiting reagent..........<br />
<br />
Please help me</div>

]]></content:encoded>
			<category domain="http://www.askmehelpdesk.com/chemistry/">Chemistry</category>
			<dc:creator>sarah1004</dc:creator>
			<guid isPermaLink="true">http://www.askmehelpdesk.com/chemistry/one-limiting-reagent-417904.html</guid>
		</item>
		<item>
			<title>calculate the specific heat of the metal.</title>
			<link>http://www.askmehelpdesk.com/chemistry/calculate-specific-heat-metal-417530.html</link>
			<pubDate>Thu, 19 Nov 2009 18:54:36 GMT</pubDate>
			<description>A piece of a metal (34.9g) was heated to about 95C and then added to 550g water with the initial temperature of 28.2C. If the final temperature of the water and the metal is 31.2C, calculate the specific heat of the metal. 
 
Do we have any formula for this problem? 
 
Thanks</description>
			<content:encoded><![CDATA[<div>A piece of a metal (34.9g) was heated to about 95C and then added to 550g water with the initial temperature of 28.2C. If the final temperature of the water and the metal is 31.2C, calculate the specific heat of the metal.<br />
<br />
Do we have any formula for this problem?<br />
<br />
Thanks</div>

]]></content:encoded>
			<category domain="http://www.askmehelpdesk.com/chemistry/">Chemistry</category>
			<dc:creator>sarah1004</dc:creator>
			<guid isPermaLink="true">http://www.askmehelpdesk.com/chemistry/calculate-specific-heat-metal-417530.html</guid>
		</item>
		<item>
			<title>calculate the quantity of heat lost</title>
			<link>http://www.askmehelpdesk.com/chemistry/calculate-quantity-heat-lost-417372.html</link>
			<pubDate>Thu, 19 Nov 2009 06:06:37 GMT</pubDate>
			<description>calculate the quantity of heat lost when 52g of S is cooled from 85C to 60C. 
The specific heat of sulfur is 0.736J/g C. 
 
Do i have to find mole of S first? 
 
Please help the step to solve this problem.Thanks</description>
			<content:encoded><![CDATA[<div>calculate the quantity of heat lost when 52g of S is cooled from 85C to 60C.<br />
The specific heat of sulfur is 0.736J/g C.<br />
<br />
Do i have to find mole of S first?<br />
<br />
Please help the step to solve this problem.Thanks</div>

]]></content:encoded>
			<category domain="http://www.askmehelpdesk.com/chemistry/">Chemistry</category>
			<dc:creator>sarah1004</dc:creator>
			<guid isPermaLink="true">http://www.askmehelpdesk.com/chemistry/calculate-quantity-heat-lost-417372.html</guid>
		</item>
		<item>
			<title>given the reactants how do u find the products</title>
			<link>http://www.askmehelpdesk.com/chemistry/given-reactants-how-do-u-find-products-417342.html</link>
			<pubDate>Thu, 19 Nov 2009 03:35:47 GMT</pubDate>
			<description>how do i find the products or these following reactants? 
 
Na2CO3 +HCl 
 
C6H12O6 
 
CuSO4 
 
AgNO3 + NaI</description>
			<content:encoded><![CDATA[<div>how do i find the products or these following reactants?<br />
<br />
Na2CO3 +HCl<br />
<br />
C6H12O6<br />
<br />
CuSO4<br />
<br />
AgNO3 + NaI</div>

]]></content:encoded>
			<category domain="http://www.askmehelpdesk.com/chemistry/">Chemistry</category>
			<dc:creator>stacey_113</dc:creator>
			<guid isPermaLink="true">http://www.askmehelpdesk.com/chemistry/given-reactants-how-do-u-find-products-417342.html</guid>
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		<item>
			<title>Chemical Reactions: Balanced Chemical Equations</title>
			<link>http://www.askmehelpdesk.com/chemistry/chemical-reactions-balanced-chemical-equations-417322.html</link>
			<pubDate>Thu, 19 Nov 2009 02:04:45 GMT</pubDate>
			<description><![CDATA[How do you do a structural diagram of reactant molecules 
 
2 no + )2 -> 2no3  
 
structural digram of product molecules]]></description>
			<content:encoded><![CDATA[<div>How do you do a structural diagram of<font color="magenta"> reactant </font>molecules<br />
<br />
2 no + )2 -&gt; 2no3 <br />
<br />
structural digram of <font color="magenta">product </font>molecules</div>

]]></content:encoded>
			<category domain="http://www.askmehelpdesk.com/chemistry/">Chemistry</category>
			<dc:creator>claudia laura</dc:creator>
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		<item>
			<title>what is the oxidation number of.</title>
			<link>http://www.askmehelpdesk.com/chemistry/what-oxidation-number-417301.html</link>
			<pubDate>Thu, 19 Nov 2009 00:39:26 GMT</pubDate>
			<description><![CDATA[2KMnO_4\ + 10K_2S_2O_3 + 16HCl \rightarrow 2MnCl_2 + 5K_2S_4O_6 + 12KCl + 8H_2O   
 
what is the oxidation number of 
 
Mn in MnCl2    --> +2 
Mn in MnO4^-    ----> 
S in K2S4O6   ----------> +10 
Cl in HCl  ------>+1 
 
I couldnt do (Mn in MnO4^-    ---->) this one and also i am not sure on third...]]></description>
			<content:encoded><![CDATA[<div><img rel="novbseo" src="http://www.askmehelpdesk.com/cgi-bin/mimetex.cgi?2KMnO_4\ + 10K_2S_2O_3 + 16HCl \rightarrow 2MnCl_2 + 5K_2S_4O_6 + 12KCl + 8H_2O  "><br />
<br />
what is the oxidation number of<br />
<br />
Mn in MnCl2    --&gt; +2<br />
Mn in MnO4^-    ----&gt;<br />
S in K2S4O6   ----------&gt; +10<br />
Cl in HCl  ------&gt;+1<br />
<br />
I couldnt do (Mn in MnO4^-    ----&gt;) this one and also i am not sure on third one either..<br />
Please help me ohh.. do i have to multiply coefficant to each molecule before looking for oxidation number?</div>

]]></content:encoded>
			<category domain="http://www.askmehelpdesk.com/chemistry/">Chemistry</category>
			<dc:creator>sarah1004</dc:creator>
			<guid isPermaLink="true">http://www.askmehelpdesk.com/chemistry/what-oxidation-number-417301.html</guid>
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		<item>
			<title>write balanced chemical equation for the reaction, I did it! but i am not sure.</title>
			<link>http://www.askmehelpdesk.com/chemistry/write-balanced-chemical-equation-reaction-did-but-am-not-sure-417025.html</link>
			<pubDate>Wed, 18 Nov 2009 06:27:31 GMT</pubDate>
			<description><![CDATA[write the balanced chemical equation for the reaction of Fe2+ with MnO4- in acidic solution. 
 
I did it , but i am not sure. please check it for me 
 
H^+ + MnO4^- + Fe2+ ---------------> Mn2+ + Fe3+ + H2O]]></description>
			<content:encoded><![CDATA[<div>write the balanced chemical equation for the reaction of Fe2+ with MnO4- in acidic solution.<br />
<br />
I did it , but i am not sure. please check it for me<br />
<br />
H^+ + MnO4^- + Fe2+ ---------------&gt; Mn2+ + Fe3+ + H2O</div>

]]></content:encoded>
			<category domain="http://www.askmehelpdesk.com/chemistry/">Chemistry</category>
			<dc:creator>sarah1004</dc:creator>
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		<item>
			<title>I am reallly confusing this is True or not.</title>
			<link>http://www.askmehelpdesk.com/chemistry/am-reallly-confusing-true-not-417019.html</link>
			<pubDate>Wed, 18 Nov 2009 05:42:45 GMT</pubDate>
			<description><![CDATA[a)&#9651;H for the reaction of NaOH and HCl solutions will be the same as &#9651;H for reaction of KOH and HNO3 solutions because the net ionic equation is the same in each case. 
 
b)&#9651;H for the reaction of NaOH and HCl solutions will be different from &#9651;H for the reaction between LiOH and HBr because different...]]></description>
			<content:encoded><![CDATA[<div>a)&#9651;H for the reaction of NaOH and HCl solutions will be the same as &#9651;H for reaction of KOH and HNO3 solutions because the net ionic equation is the same in each case.<br />
<br />
b)&#9651;H for the reaction of NaOH and HCl solutions will be different from &#9651;H for the reaction between LiOH and HBr because different salt is formed.<br />
<br />
I think a is true and b is false...<br />
<br />
If not.... I will think about it again please tell me &gt;0&lt;</div>

]]></content:encoded>
			<category domain="http://www.askmehelpdesk.com/chemistry/">Chemistry</category>
			<dc:creator>sarah1004</dc:creator>
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