write a balanced reaction between Ba(OH)2 and H2SO4.

sarah1004 · #1 Nov 2, 2009, 08:21 AM

write a balanced reaction between Ba(OH)2 and H2SO4.
----> Ba(OH)2(aq) + H2SO4(aq) => BaSO4(s) + 2H2O(l)

explain the observed changes in conductivity.
----> H2SO4-strong conductivity. Ba(OH)2-weak conductivity.

Please check these answers are correct or not , if not please explain for me

Thanks

Unknown008 · Nov 2, 2009, 09:05 AM

Well, at first you had Ba(SO4)2 and H2SO4 which are both electrolytes. Then, you have BaSO4 which is a solid, insoluble in water. A solid does not conduct electricity, nor does pure water. So, conductivity decreases.

sarah1004 · Nov 2, 2009, 09:11 AM

write a balanced reaction between Ba(OH)2 and H2SO4.
----> Ba(OH)2(aq) + H2SO4(aq) => BaSO4(s) + 2H2O(l)

So, this equation is correct?

Thanks for your explain

Unknown008 · Nov 2, 2009, 09:16 AM

Yup, you can self check it. Count the number of Ba, H, S, O on the right and then on the left. You'll see they are equal in number.

sarah1004 · Nov 2, 2009, 09:19 AM

yes its perfectly balanced!

thanks

Unknown008 · Nov 2, 2009, 09:23 AM

You're welcome

pramod awasthi · Nov 9, 2009, 04:52 AM

reaction is
Ba(OH)2 + H2SO4 ====> BaSO4 + 2H2O
it is a balane equation and coductivity is depand upon capacity to dissociate in to ions. an BaSO4 have less capabilty to produce ions than H2SO4 and Ba(OH)4



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