Can someone help me with this problem?

A solution of calcium hydroxide required 26.42 ml to neutralize .914 g of potassium hydrogen phthalate. What was the molarity of the calcium hydroxide solution? This equation is given:

Ca(OH)[SIZE=1]2[/SIZE] + 2KHC[SIZE=1]8[/SIZE]H[SIZE=1]4[/SIZE]O[SIZE=1]4[/SIZE]= CaC[SIZE=1]8[/SIZE]H[SIZE=1]4[/SIZE]O[SIZE=1]4[/SIZE]+ K[SIZE=1]2[/SIZE]C[SIZE=1]8[/SIZE]H[SIZE=1]4[/SIZE]O[SIZE=1]4[/SIZE] + 2H[SIZE=1]2[/SIZE]O

The molarity of the potassium hydrogen phthalate is .914 g/.02642 L. or 34.60 g / L. I can get that. I'm confused as how to determine the molarity of the calcium hydroxide.

joseph2000

Hi
You got it wrong. Molarity refers to the number of moles of solute per liter of solution. Number of moles is equal to mass of pure materials divided by its molecular mass. In your problem solved first the molarity of a given material. then balanced the chemical reaction. you can predict now the number of moles of the unknown material then use that as the data for the calculation of molarity using the definition.