A 38mL solution 0.026M solution of HCl reacts with a 0.032M NaOH.

HCl+NaOH=NaCl+H2O
number of moles of HCl originally present is 0.000988moles.

how many moles of NaOH are needed to neutralize the acid???
Please show me how to do this and , Please give me answer. Please..

sarah1004

31250/0.000988=3.16x10^7

like this?...

Unknown008

Nope. Look back at my example. How did I get the volume of HCl for 0.23 moles?

sarah1004

1000/0.000988=1.01x10^6

like this is correct ?..

Thank you!

Unknown008

No again.

The answer is:

0.032 moles -> 1000 mL
1 mole -> 1000/0.032 = 31250 mL
0.000988 mol -> 31250*0.000988 = 30.875 mL

Just in case, '*' means multiplication.

sarah1004

Oh.....
now i got it thank you so much....

So, we can conclude like it

A 38mL solution 0.026M solution of HCl reacts with a 0.032M NaOH.

a)write a balanced chemical reaction for the above process.
HCl+NaOH=NaCl+H2O

b)calculate the number of moles of HCl originally present.
(0.026moles/Liter)*(38mL/1)*(1Liter/1000mL)=0.000988moles.

c)how many moles of NaOH are needed to neutralize the acid?
(0.026/1000)*38=0.000988mloles

d)calculate the volume of the NaOH required to react completely with the acid.
31250*0.000988=30.875mL


Can you check it out for me?
Thank you sososo much

Unknown008

Well done!

sarah1004

Thank you
Are you a teacher?

Unknown008

Nope, a student. Perhaps. at a slightly higher level than you...