How many moles of NaOH are needed to neutralize the acid?

A 38mL solution 0.026M solution of HCl reacts with a 0.032M NaOH.

HCl+NaOH=NaCl+H2O
number of moles of HCl originally present is 0.000988moles.

how many moles of NaOH are needed to neutralize the acid???

 sarah1004 Posts: 107, Reputation: 1 Junior Member #11 Oct 22, 2009, 12:07 PM
31250/0.000988=3.16x10^7

like this?.
 Unknown008 Posts: 8,147, Reputation: 3745 Uber Member #12 Oct 22, 2009, 12:12 PM

Nope. Look back at my example. How did I get the volume of HCl for 0.23 moles?
 sarah1004 Posts: 107, Reputation: 1 Junior Member #13 Oct 22, 2009, 12:15 PM
1000/0.000988=1.01x10^6

like this is correct?.

Thank you!
 Unknown008 Posts: 8,147, Reputation: 3745 Uber Member #14 Oct 22, 2009, 12:20 PM

No again.

0.032 moles -> 1000 mL
1 mole -> 1000/0.032 = 31250 mL
0.000988 mol -> 31250*0.000988 = 30.875 mL

Just in case, '*' means multiplication.
 sarah1004 Posts: 107, Reputation: 1 Junior Member #15 Oct 22, 2009, 12:27 PM
Oh...
now I got it thank you so much...

So, we can conclude like it

A 38mL solution 0.026M solution of HCl reacts with a 0.032M NaOH.

a)write a balanced chemical reaction for the above process.
HCl+NaOH=NaCl+H2O

b)calculate the number of moles of HCl originally present.
(0.026moles/Liter)*(38mL/1)*(1Liter/1000mL)=0.000988moles.

c)how many moles of NaOH are needed to neutralize the acid?
(0.026/1000)*38=0.000988mloles

d)calculate the volume of the NaOH required to react completely with the acid.
31250*0.000988=30.875mL

Can you check it out for me?
Thank you sososo much
 Unknown008 Posts: 8,147, Reputation: 3745 Uber Member #16 Oct 22, 2009, 12:28 PM

Well done!
 sarah1004 Posts: 107, Reputation: 1 Junior Member #17 Oct 22, 2009, 12:31 PM
Thank you
Are you a teacher?
 Unknown008 Posts: 8,147, Reputation: 3745 Uber Member #18 Oct 22, 2009, 11:24 PM

Nope, a student. Perhaps. At a slightly higher level than you...

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