Need my Cosmology math logic checked.

Capuchin · Jun 20, 2009, 12:24 PM

Your answer is roughly correct with respect to the center of the milky way (you might get a slightly better answer considering the sun's path as an arc). However the milky way itself will be moving much faster, swamping the local speed of the sun, I.e. Your absolute speed with reference to the center of the universe (if such a place exists) is likely to be much faster.

KUXJ · Jun 21, 2009, 07:29 AM

Quote:

Originally Posted by Capuchin

your answer is roughly correct with respect to the center of the milky way (you might get a slightly better answer considering the sun's path as an arc). However the milky way itself will be moving much faster, swamping the local speed of the sun, I.e. Your absolute speed with reference to the center of the universe (if such a place exists) is likely to be much faster.

I knew this was going to make my head hurt.

It may not be the correct representation, but using the attached image.....

* The Solar system is the small circle.
* The Milky Way is the larger circle.
* The X,why,Z co-ordinates represent the center of the Universe "if such a place
* exists" or could it stand for "my origin point".

If I understand correctly:

I have the relationship between the Solar system and Milky Way "roughly correct".

Thank You.

What I need to do now is apply the Hubble constant to my result, if I can determine, within the Universe, the distance of "my origin point" to 21,130 days later, and counting.

Edited at 2:00pm edt, 19:00z

This last statement is incorrect as to "if I can determine, within the Universe, the distance of "my origin point" to 21,130 days later, and counting." all I would need to do is apply the H-constant, I think.....

ebaines · Jun 22, 2009, 06:02 AM

Quote:

Originally Posted by KUXJ

Background

D = 273,844,800,000mi

So far so good....

Quote:

Originally Posted by KUXJ

[
To convert to LY divide by 5.879×10^12 (58,790,000,000)
Light-year - Wikipedia, the free encyclopedia

LY = 273,844,800,000 / 58,790,000,000 = 4.6580166695016159210750127572716 Light Years from Origin Point.

Correct?

Not quite - you divided the distance by 5.879 x 10^10 instead of 5.879 x 10^12. Consequently your answer is too big by a factor of 100. You should have an answer of 0.0465 LY. Remember that a light year is a very, very long distance - it just didn't seem possible that you could travel over 4 light years in only 57 years.

By the way, given that the accuracy of the speed of light is given to only 4 digits, there is no point in writing out the results of the division to anything more than 4 decimal places.

KUXJ · Jun 22, 2009, 09:05 AM

Quote:

Originally Posted by ebaines

it just didn't seem possible that you could travel over 4 light years in only 57 years.

Oh...I don't know, I'll be 58 in Aug. And the older I get, the faster time seems to go by

Thank You for the insight,

Regards

KUXJ

KUXJ · Jul 20, 2009, 08:21 PM

Just an update:

I sent an email to NDTyson at the Hayden 'bout my question,
And we are in dialog whether the H0 or Newton's laws of orbital Mechanics should be used.

That's how it was signed. Might just be a member of his staff.

Home | Neil deGrasse Tyson

K

KUXJ · Nov 6, 2009, 09:49 AM

Have received answer:

The Hubble constant remains irrelevant at these scales of distance and time. Simply Earth's rotation, Earth's revolution around the Sun, the Sun's revolution around the MIlky Way galaxy's enter, and the falling of the Milky way towards the Andromeda galaxy. There is no other relevant motion to your needs.

-NDTyson

So for now, it remains .0465 LY

Need my Cosmology math logic checked.

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