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ABDI9
Oct 22, 2011, 05:33 AM
v^-u^/2a=u t 1/2 a t^
make v the subject when a=0.75, u=3.6 and t=10.5

Unknown008
Oct 22, 2011, 07:36 AM
The aim is to get v alone by adding/subtracting/multiplying/dividing (or other operations) both sides by a certain value.

1. Multiply both sides by 2a.
2. Add u^2 to both sides.
3. Take the square root of both sides.

Can you do that?

ABDI9
Oct 25, 2011, 01:17 PM
Hi
SORRY FOR THE LATE RESPONSE

V^-U^/2A=UT 1/2 AT^

2A=(V^+U^)(U/T)
_________________*2A
2A

2A=(V^+U^) (V/T)

(2A+U^2) (UT+U^2)
IS THE STEPS CORRECT OF HAVE I MISSED SOMETHING

Unknown008
Oct 26, 2011, 02:59 AM
I can't understand what you did...

The first step, multiply by 2a on both sides:

\frac{v^2 - u^2}{2a} \times 2a = \(ut + \frac12 at^2\) \times 2a

Simplify to get:

v^2 - u^2 = 2a\(ut + \frac12 at^2\)

Can you continue?