Markovnikov'v rule explains the regiochemistry in the addition of unsymmetrical reactants to alkenes. Most commonly this is seen in the addition of water (H-OH) and hydrogen bromide (H-Br). For Markovnikov's rule to hold sway, the reaction must proceed through a carbocation mechanism, The Markovnikov product is, of course, formed from the more stable carbocation. As an example of this, look at the addition of water to propene under acid catalysis: CH3CH=CH2 + H-OH ---H+--> CH3CHOHCH3. 2-Propanol is the "Markovnikov Product"
The hydroboration/oxidation sequence gives, as you tell, the other isomeric propanol (1-propanol). This is the "AntiMarkovnikov Product" We also see this reversal of regiochemistry with the addition of HBr in the absence (Markovnikov) and presence (AntiMarkovnikov) of peroxides.
I think it should always be pointed out that in antiMarkovnikov additions the RULE still holds true - it is the reactants that are altered. When H-OH is added with acid catalysis the major product is formed from the more stable carbocation. Stoichiometrically, you add H+ then OH-. If you examine the mechanism of hydroboration/oxidation you see that the sequence results in the addition of H- then OH+ -- you have reversed the polarity of water!! (BH3 is s borohydrIDE) In HBr addition, the difference is the ionic vs the radical mechanisms.
I hope this works for you. A picture is worth a thousand words but I have a new computer and no Chemdraw yet.