fletcher123
Dec 9, 2009, 12:24 PM
(Sin / 1+sin) + sec^2 = tan sec + 1
please help
Alty
Dec 9, 2009, 12:27 PM
What have you figured out so far?
Post the work you've already done and then we can tell you where you went wrong.
ebaines
Dec 11, 2009, 01:33 PM
What you have written appears to be this:
\frac {sin(x)} {1+ sin(x)} + sec^2(x)= tan(x)sec(x)+1
It is always good with this type of problem to first convert the tan(x) and sec(x) functions into their sin(x) and cos(x) equivalents. Then it's just a matter of combining fractions, and using identities such as cos^2(x) = 1 - sin^2(x). Post back if you're still having difficulty, but show us what you've tried.