jordo6889
Nov 5, 2009, 10:12 AM
Find an equation of the form y=ax^2+bx+c whose graph passes through the points (-1,-4), (-3,-14) and (4,-14).
Perito
Nov 5, 2009, 10:31 AM
Find an equation of the form y=ax^2+bx+c whose graph passes through the points (-1,-4), (-3,-14) and (4,-14).
y=ax^2 + bx + c
Substituting point #1:
-4 = a(-1)^2 + b(-1) + c
Substituting point #2
-14 = a(-3)^2 + b(-3) + c
Substituting point #3
-14 = a(4)^2 + b(4) + c
If I did everything correctly, you now have three independent equations, and three unknowns. Solve the set of simultaneous equations for a, b, and c.