jordo6889
Nov 5, 2009, 09:12 AM
Find an equation of the form y=ax^2+bx+c whose graph passes through the points (-1,-4), (-3,-14) and (4,-14).
jordo6889 Nov 5, 2009, 09:12 AM Find an equation of the form y=ax^2+bx+c whose graph passes through the points (-1,-4), (-3,-14) and (4,-14). Perito Nov 5, 2009, 09:31 AM Find an equation of the form y=ax^2+bx+c whose graph passes through the points (-1,-4), (-3,-14) and (4,-14). y=ax^2 + bx + c Substituting point #1: -4 = a(-1)^2 + b(-1) + c Substituting point #2 -14 = a(-3)^2 + b(-3) + c Substituting point #3 -14 = a(4)^2 + b(4) + c If I did everything correctly, you now have three independent equations, and three unknowns. Solve the set of simultaneous equations for a, b, and c. Copyright ©2005-, Ask Me Help Desk
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