shegun4u
Nov 4, 2009, 04:53 AM
E=mgh+1/2mv(squared) for h
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shegun4u Nov 4, 2009, 04:53 AM E=mgh+1/2mv(squared) for h Perito Nov 4, 2009, 05:06 AM Subtract 1/2 mv^2 from both sides. Can you figure it out now? shegun4u Nov 4, 2009, 05:36 AM Subtract 1/2 mv^2 from both sides. Can you figure it out now? no. can you write it out? thanks Nhatkiem Nov 4, 2009, 10:52 AM no. can you write it out? thanks If you subtract \frac{mv^2}{2} from both sides, you then have E-\frac{mv^2}{2}=mgh You only need to isolate h now, there is a leading coefficient of "mg" on h. Divide both sides by this coefficient to isolate h. Copyright ©2005-, Ask Me Help Desk
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