E=mgh+1/2mv(squared) for h

Subtract 1/2 mv^2 from both sides. Can you figure it out now?

Subtract 1/2 mv^2 from both sides. Can you figure it out now?

no. can you write it out?
Thanks

no. can you write it out?
thanks

If you subtract \frac{mv^2}{2} from both sides, you then have

E-\frac{mv^2}{2}=mgh

You only need to isolate h now, there is a leading coefficient of "mg" on h. Divide both sides by this coefficient to isolate h.