1) This would be total saturation (RH = 100%).
2)Yes, it is possible; for moist air parcels. Moist air parcels cool at a smaller rate, then dry air parcels due to the release of latent heat during condensation. Essentially, if you get a moist air parcel, that has enough positive buoyancy, you can get thunderstorm development. To be conditionally stable means that the atmosphere is unstable for moist air parcels and stable for dry air parcels.
3)The parcel with the higher amount of water vapor would experience condensation or deposition of water vapor at a lower altitude compared to the parcel with the least water vapor. When it comes to condensation of water vapor, the amount of water vapor matters. The more water vapor in a parcel, the sooner it will condense and the less water vapor in a parcel, the more lifting that will be needed to cause condensation.
4) Relative humidity depends solely on the actual amount of moisture and temperature. If bring air in from outside during the winter and therefore increase the temperature, you also increase the amount of water vapor needed for saturation. Absolute humidity on the other hand depends solely on moisture and the volume of dry air it occupies, as it's the ratio of the actual amount of water vapor per unit volume of dry air. So the relative humidity is lower inside a house and higher outside the house due to the dependence on the temperature. The absolute humidity is higher in the house then it is outside, because again it solely depends on the amount of moisture and the volume of dry air that moisture occupies.
5) There is a trick to this. For every 10 degrees C in temperature increase, the relative humidity gets divided in half. So if you increase the temperature by 20 degrees C, then you would take (1/4)*(.90) = 0.225 = 22.5%
6) Since the relative humidity of the parcel remains below 100%, then you can lift the parcel dry adiabatically as such:
Dry Adiabatic Lapse Rate = -9.8 degrees C/1000 m
Since our change in elevation is 2500 m, then we multiply -9.8 degrees C by (2500 m/1000m) = -9.8 degrees C *2.5 = -24.5 degrees C
Therefore add the original temperature and the temperature change together:
0 degrees C - 24.5 degrees C = -24.5 degrees C<---Answer
7) a. Stable for dry and moist air parcels.
B. Stable for dry air parcels, neutral for moist air parcels.
C. Stable for dry air parcels, unstable for moist air parcels.
D. Unstable for both dry and moist air parcels.
E. Stable for both dry and moist air parcels.
F. Unstable for both dry and moist air parcels.